Basic Algebra word problem

I am here with another interesting concept of Math i.e. Solving algebra word problem. Algebra word problem is just like a story. When you solved story problems in your math class you had to decide what information you had and what you needed to find out.You need to decide what operation it requires whether addition, subtraction, multiplication or division. Addition is used to find the total and subtraction is used to find the changes in the values. Word problems are solved by separating information from the problems into two equal groups, one for each side of an equation. Interesting story right.

We have vast topics in algebra word problems and to make you understand i have some simple examples with different methods of solving algebra word problem below which will help you.

Example for solving algebra word problem.

Example 1. Tom has 15 mangoes and 12 apples, how many fruits does he have in total.

We all know that the sum of 15 and 12 is equal to the the total amount of fruit. an unknown number or value is represented by a letter. The total number of pieces of fruit is unknown, so we will represent that amount with x. When the value that a particular variable will represent is determined, it is defined by writing a statement like,

Let x = Total Amount of Fruit

Once again, the sum of 15 mangoes and 12 apples is equal to the total amount of fruit. This can be used to translate the problem into an equation, like the following:

15 + 12 = x

Now solve the equation which was created in the last step.

Let x = Total Pieces of Fruit.

Initial equation = 15+12=27

After combining like terms 27=x

Therefore he had 27 pieces of fruits with him.

Example 2:-

John has 19 more nickels than quarters. Solve the word problem and find how many coins he has, if the total value of his coins are $3.65?

Answer:

Let us consider, n = The number of nickels and q = The number of quarters.

John has 19 more nickels than quarters can be written as q + 19 = n.

We know,

one quarter = 25cents.

one nickel = 5cents.

Therefore,

$3.65 = 365 cents.

The total value of his coins are $3.65 can be written in an equation as 5n + 25q = 365

Solving both equations we have,

q + 19 = n

25q + 5n = 365

25q + 5(q + 19) = 365

25q + 5q + 95 = 365

30q = 270

q = 270 / 30

After solving, we get

q = 9

Substitute the q value in n = q + 19, we get

n = q + 19

n = 9 + 19

n = 28.

Answer:

The total coins he have 37.

Example 3:-

Solve the following equation:

Answer:

I have solved three different examples of solving algebra word problem, different methods are used in it. How do you find the above examples? i am sure it is useful but it will be more useful only if you practice it. The more and more you practice the more you become perfect. But don't forget to post your comments as you know i am waiting for it.